Matematika Sekolah Menengah Pertama Quis

a = 5²
b = 2²
c = 80

Tentukan 5a + 7b - 8c × 2

Quis

a = 5²
b = 2²
c = 80

Tentukan 5a + 7b - 8c × 2

5a + 7b - 8c × 2 = -1.127

__________________________

JIKA:

a = 5²

a = 5 × 5

a = 25

..............

b = 2²

b = 2 × 2

b = 4

..............

c = 80

____________

DIKET:

a = 25

b = 4

c = 80

.

PENYELESAIAN:

5a + 7b - 8c × 2

= 5(25) + 7(4) - 8(80) × 2

= (5 × 25) + (7 × 4) - (8 × 80) × 2

= 125 + 28 - (640 × 2)

= 125 + 28 - 1.280

= 153 - 1.280

= -1.127

Hasil 5a + 7b - 8c × 2 adalah -1127

PENYELESAIAN :

Diketahui

  • a = 5²
  • b = 2²
  • c = 80

Ditanya

  • Tentukan 5a + 7b - 8c × 2

Jawab

= a

= 5²

= 5 × 5

= 25

= b

= 2²

= 2 × 2

= 4

_____________________

= 5a + 7b - 8c × 2

= 5(5²) + 7(2²) - 8(80) × 2

= 5(25) + 7(4) - 640 × 2

= 125 + 28 - 640 × 2

= 125 + 28 - 1.280

= 153 - 1.280

= -1.127

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